1960 IMO Problem 3

Tagged: ,

  • This topic is empty.
Viewing 1 post (of 1 total)
  • Author
  • Vinuthan S

    1960 IMO Problem 3


    In a given right triangle $ABC$, the hypotenuse $BC$ , of length a, is divided into $n$ equal parts (n and odd integer). Let $\alpha$  be the acute angel subtending, from A, that segment which contains the midpoint of the hypotenuse. Let h be the length of the altitude to the hypotenuse of the triangle.

    Prove that: \[ \tan{\alpha}=\dfrac{4nh}{(n^2-1)a}. \]


Viewing 1 post (of 1 total)
  • You must be logged in to reply to this topic.

Copyright © 2021. Maintained by VASISTA Eduventures. All rights reserved