Sainik School Maths Approximation Question 6 to 10

Sainik School Maths Approximation Question 6 to 10

6. 18.24 when multiplied by 20.0, we get the approximate result is

  1. 365

  2. 368

  3. 364

  4. 362

7. what approximate value should come in place of question mark(?)?

840.0003/23.999=?

  1. 47

  2. 8

  3. 35

  4. 18

8. what is the approximate value of (8531 + 6307 + 1093)÷ (501 + 724 + 396)?

  1. a.10

  2. b.7

  3. c.16

  4. d.13

9. Calculate the value (897 + 635 + 468 – 120 – 721) its nearest hundred.

  1. 110

  2. 1200

  3. 1300

  4. 1000

10. approximation value of (6.97 × 0.093) is

  1. 0.7

  2. 0.8

  3. 7.0

  4. 8.0

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