Sainik School Maths Approximation Question 6 to 10

6. 18.24 when multiplied by 20.0, we get the approximate result is

  1. 365

  2. 368

  3. 364

  4. 362

7. what approximate value should come in place of question mark(?)?

840.0003/23.999=?

  1. 47

  2. 8

  3. 35

  4. 18

8. what is the approximate value of (8531 + 6307 + 1093)÷ (501 + 724 + 396)?

  1. a.10

  2. b.7

  3. c.16

  4. d.13

9. Calculate the value (897 + 635 + 468 – 120 – 721) its nearest hundred.

  1. 110

  2. 1200

  3. 1300

  4. 1000

10. approximation value of (6.97 × 0.093) is

  1. 0.7

  2. 0.8

  3. 7.0

  4. 8.0

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Sainik School Maths Approximation Question 1 to 5

1. 1372 ÷ 28 × x – 1653 = 748

  1. 49

  2. 13

  3. 15

  4. 18

2. What is the approximation value of 275.0003 × 3.005?

  1. 825

  2. 830

  3. 810

  4. 835

3. What is the approx. value of 16268?

  1. 16200

  2. 16300

  3. 16260

  4. 16270

4. The number 66.0684, correct to the nearest ten is

  1. 66.068

  2. 66.07

  3. 66.1

  4. 70

5. The nearest thousand of 29789 will be written as

  1. 29000

  2. 29700

  3. 29800

  4. 30000

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